若b²=r²(1+k),证明直线y=kx+b与圆x²+y²=r²相切
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![若b²=r²(1+k),证明直线y=kx+b与圆x²+y²=r²相切](/uploads/image/z/3051265-49-5.jpg?t=%E8%8B%A5b%26%23178%3B%3Dr%26%23178%3B%EF%BC%881%2Bk%EF%BC%89%2C%E8%AF%81%E6%98%8E%E7%9B%B4%E7%BA%BFy%3Dkx%2Bb%E4%B8%8E%E5%9C%86x%26%23178%3B%2By%26%23178%3B%3Dr%26%23178%3B%E7%9B%B8%E5%88%87)
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若b²=r²(1+k),证明直线y=kx+b与圆x²+y²=r²相切
若b²=r²(1+k),证明直线y=kx+b与圆x²+y²=r²相切
若b²=r²(1+k),证明直线y=kx+b与圆x²+y²=r²相切