已知:A+B=3x^2-5x-1,A-C= - 2x+3x^2-5,且|x|=1/2

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已知:A+B=3x^2-5x-1,A-C= - 2x+3x^2-5,且|x|=1/2
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已知:A+B=3x^2-5x-1,A-C= - 2x+3x^2-5,且|x|=1/2
已知:A+B=3x^2-5x-1,A-C= - 2x+3x^2-5,且|x|=1/2

已知:A+B=3x^2-5x-1,A-C= - 2x+3x^2-5,且|x|=1/2
已知:A+B=3x^2-5x-1,A-C= - 2x+3x^2-5
两式相减A+C=3x²-5x-1+2x-3x²+5
=-3x+4
已知IxI=1/2
则x=1/2或-1/2
1.x=1/2时,A+C=-3*(1/2)+4=5/2
2.x=-1/2时,A+C=-3*(-1/2)+4=11/2
(⊙ o ⊙ )

X=(4-B-C)/3

B C =A B-(A-C) =3x^2-5x 1-(- 2x 3x^2-5) =3x^2-5x 1 2x-3x^2 5 =6-3x =6-3*2 =0 把两个式子相减,式子就变成:B