已知集合M={y/y=2^x,x>0},N={y/y=lg(2x-x^2)},则M∩NA(1..2)B(1..正无穷)C〔2..整无穷)D〔1..正无穷)

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已知集合M={y/y=2^x,x>0},N={y/y=lg(2x-x^2)},则M∩NA(1..2)B(1..正无穷)C〔2..整无穷)D〔1..正无穷)
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已知集合M={y/y=2^x,x>0},N={y/y=lg(2x-x^2)},则M∩NA(1..2)B(1..正无穷)C〔2..整无穷)D〔1..正无穷)
已知集合M={y/y=2^x,x>0},N={y/y=lg(2x-x^2)},则M∩N
A(1..2)B(1..正无穷)C〔2..整无穷)D〔1..正无穷)

已知集合M={y/y=2^x,x>0},N={y/y=lg(2x-x^2)},则M∩NA(1..2)B(1..正无穷)C〔2..整无穷)D〔1..正无穷)
M={y/y=2^x,x>0},(1,正无穷)
N={y/y=lg(2x-x^2)},(负无穷,0】
则M∩N = 空集

M=(1,正无穷)
2x-x^2的值域是(负无穷,1]
但是2x-x^2只能取(0,1] 所以N=(负无穷,0]
M交N=空集