已知a,b满足a²+9b²-4a-6b+5=0,则a²-b²的值是
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/25 08:32:57
![已知a,b满足a²+9b²-4a-6b+5=0,则a²-b²的值是](/uploads/image/z/3147530-50-0.jpg?t=%E5%B7%B2%E7%9F%A5a%2Cb%E6%BB%A1%E8%B6%B3a%26%23178%3B%2B9b%26%23178%3B-4a-6b%2B5%3D0%2C%E5%88%99a%26%23178%3B-b%26%23178%3B%E7%9A%84%E5%80%BC%E6%98%AF)
xJ0_e HKi6]/0DW:)XF'z2t+xf֫4=s'A<ҧãc9>h\KwZZ\.Pfo8uv4ɉ`T][so57M'L=Ѡ]2*%t?cҁہsPg^*.2-g2Mns0k&5+9e> u3ltY
Qu!b-xWq.9Ķ5#D_TYU4i ձ2sr9zѶ&cDMBk6,
已知a,b满足a²+9b²-4a-6b+5=0,则a²-b²的值是
已知a,b满足a²+9b²-4a-6b+5=0,则a²-b²的值是
已知a,b满足a²+9b²-4a-6b+5=0,则a²-b²的值是
a²+9b²-4a-6b+5=0
→(a²-4a+4)+(9b²-6b+1)=0
→(a-2)²+(3b-1)²=0.
∴a=2,b=1/3.
从而,a²-b²=4-1/9=35/9.
即(a²-4a+4)+(9b²-6b+1)=0
(a-2)²+(3b-1)²=0
所以a-2=0,3b-1=0
a=2,b=1/3
所以原式=2²-(1/3)²=35/9
0=a²+9b²-4a-6b+5=a²-4a+4+9b²-6b+1=(a-2)²+(3b-1)²因此a-2=0,以及3b-1=0,a=2而b=1/3.因此a²-b²=35/9
您好:
a²+b²-4a-6b+13=0
(a²-4a+4)+(b²-6b+9)=0
(a-2)²+(b-3)²=0
a=2 b=3
a²+b²
=2²+3²
=13