40(X-1)+(X-2)=10(X-1)+X+58

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40(X-1)+(X-2)=10(X-1)+X+58
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40(X-1)+(X-2)=10(X-1)+X+58
40(X-1)+(X-2)=10(X-1)+X+58

40(X-1)+(X-2)=10(X-1)+X+58
40(X-1)+(X-2)=10(X-1)+X+58
40x-40+x-2=10x-10+x+58
30x=90
x=3

拒绝回答!!!

40(X-1)+(X-2)=10(X-1)+X+58
40x-40+x-2=10x-10+x+58
30x=100
x=3/10

40(X-1)+(X-2)=10(X-1)+X+58
解:40X-40+X-2=10X-10+X+58
41X-42=11X+48
30X=90
X=3

40(X-1)+(X-2)=10(X-1)+X+58
40X-40+X-2=10X-10+X+58
40X+X-10X-X=40+2-10+58
30X=90
X=3

小学几年级拉？

解方程(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=1 X+X+X+(X-1)+(X-2)+(X-3)+(X-4)=10(X-3)+(X-4) 1+x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11+x^12=97.8x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11+x^12=97.8 好多年没有用过过数学公式了 想不起来怎么算了 想知道 X值是多少 已知x=2π+1求 |x-1|+|x-2|+|x-3|+|x-4|+|x-5|+|x-6|+|x-7|+|x-8|+|x-9|+|x-10| 已知x=2π+1.求(X-1)+(X-2)+(X-3)+(X-4)+(X-5)+(X-6)+(X-7)+(X-8)+(X-9)+(X-10) 1+x+x^2+x^3+x^4+x^5+x^6+x^7+x^8+x^9+x^10+x^11=17.7这个方程怎么样求解? x/x-2+x-9/x-7=x+1/x-1+x-8/x-6, x/x-2+x-9/x-7=x+1/x-1+x-8/x-6, (x+2)(x^2+5x-10)-(x+2)^2(x-1),其中x=1.5 (x+2)(x^2+5x-10)-(x+2)^2(x-1),其中x=1.5, x{x+1}{x-1}}x-2}{x-3}-40 x/x平方-x+2=2x/x+1 (X+1)X(X+2)X(X+3)=504 1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550必须用解方程 一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 *-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || 1x()+2x()+3x()+4x()+5x()+6x()+7x()+8x()加9x()+10x()=1980