1.(x+2y-3z)(x-2y+3z)(利用乘法公式来解答).
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/25 19:52:59
x)3{BۨRNGרRyڱOvxy5O?N*гI*ҧ;`i
m
tlt.3i! TIC*m˪8#MHB$P K?Ч;7?u$ف
"
1.(x+2y-3z)(x-2y+3z)(利用乘法公式来解答).
1.(x+2y-3z)(x-2y+3z)(利用乘法公式来解答).
1.(x+2y-3z)(x-2y+3z)(利用乘法公式来解答).
(x+2y-3z)(x-2y+3z)
=[x+(2y-3z)][x-(2y-3z)]
=x^2-(2y-3z)^2
=x^2-(4y^2-12yz+9z^2)
=x^2-4y^2+12yz-9z^2
运用平方差公式
1.已知x:y:z=4:5:7,求:(一)2x+3y+z/5z; (二)x+y/y+z 非常急,
1.(x+y-z)+(x-y+z)-(x-y-z) 2.2x-(3x-2y+3)-(5y-2)
因式分解:z^2(x-y)-4(x-y)-3z(y-x)
已知xyz≥0,x+y+z=1,化简x(2y-z)/(1+x+3y)+y(2z-x) /(1+y+3z) +z(2x-y)/(1+z+3x)
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
化简下列式子-(7X-Y-2Z)-{[4X-(X-Y-Z)-3X+Z]-X}
(2x-3y+z)-3{x-2【-z+(x-y)】-(3y-5z)}
xyz是正实数,求证:x/(y+z)+y/(z+x)+z/(x+y)>=3/2
已知(1)X-Y+Z=0 (2)X+2Y-3Z=0 求X:Y:Z
(x+2y-3z)²
已知2x+3y-4z=0,3x+4y+5z=0,求x+y+z/(除以)x-y+z的值.
已知x::y:z=3:4:5,(1)求x+y分之z的值;(2)若x+y+z=6,求x,y,z.
已知x,y,z∈(0,+∞)求证:√x^+xy+y^+√y^+yz+z^+√z^+zx+x^>=3/2(x+y+z )
2(x+y)(x+y-z)+3(y-z)(x+y-z)
数学题(x-y)/(y-z),(y-z)/(z-x),(z-x)/(x-y)已知有理数X,Y,Z两两不相等,则(x-y)/(y-z),(y-z)/(z-x),(z-x)/(x-y)中负数的个数是()A.1个 B.2个 C.3个 D.0个或2个
(x-3y+2z)(x+3y-2z)
(x-2y+3z)(x+2y-3z)