已知函数f(x)=loga(1+x),其中a>1.【1】 比较1/2[f(0)+f(1)]与f(1/2)的大小;【2】 探索1/2[f(x1-1)+f(x2-1)]0,x2>0恒成立.加急!在线等.
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![已知函数f(x)=loga(1+x),其中a>1.【1】 比较1/2[f(0)+f(1)]与f(1/2)的大小;【2】 探索1/2[f(x1-1)+f(x2-1)]0,x2>0恒成立.加急!在线等.](/uploads/image/z/3181021-61-1.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Dloga%EF%BC%881%2Bx%EF%BC%89%2C%E5%85%B6%E4%B8%ADa%3E1.%E3%80%901%E3%80%91++++++++%E6%AF%94%E8%BE%831%2F2%5Bf%280%29%2Bf%281%29%5D%E4%B8%8Ef%EF%BC%881%2F2%29%E7%9A%84%E5%A4%A7%E5%B0%8F%EF%BC%9B%E3%80%902%E3%80%91++++%E6%8E%A2%E7%B4%A21%2F2%5Bf%28x1-1%29%2Bf%28x2-1%29%5D0%2Cx2%3E0%E6%81%92%E6%88%90%E7%AB%8B.%E5%8A%A0%E6%80%A5%21%E5%9C%A8%E7%BA%BF%E7%AD%89.)
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