[(x+2y)^2 -(x+y)(3x-y)-5y^2]÷2xx=-2y=二分之一
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[(x+2y)^2 -(x+y)(3x-y)-5y^2]÷2xx=-2y=二分之一
[(x+2y)^2 -(x+y)(3x-y)-5y^2]÷2x
x=-2
y=二分之一
[(x+2y)^2 -(x+y)(3x-y)-5y^2]÷2xx=-2y=二分之一
原式=(x²+4xy+4y²-3x²-2xy+y²-5y²)÷2x
=(-2x²+2xy)÷2x
=-x+y
楼上说的对
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