数列{an}满足a1=1,an+1=根号(an^2+2)(n属于N*),则该数列的通项公式an=
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数列{an}满足a1=1,an+1=根号(an^2+2)(n属于N*),则该数列的通项公式an=
数列{an}满足a1=1,an+1=根号(an^2+2)(n属于N*),则该数列的通项公式an=
数列{an}满足a1=1,an+1=根号(an^2+2)(n属于N*),则该数列的通项公式an=
(an+1)^2=an^2+2
设bn=an^2
bn+1=bn+2
明显的迭加
b2=b1+2
b3=b2+2
...
bn+1=bn+2
等式左方加在一起 右面加在一起
bn+1=b1+2n
b1=1
bn+1=2n+1
an+1=√(2n+1)
an=√[2(n-1)+1]
an=√(2n-1)
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