若x²-x-2=0,则(x²-x)²-2+根号3分之x²-x-1的值等于?
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/13 21:00:48
![若x²-x-2=0,则(x²-x)²-2+根号3分之x²-x-1的值等于?](/uploads/image/z/325885-13-5.jpg?t=%E8%8B%A5x%26%23178%3B-x-2%3D0%2C%E5%88%99%EF%BC%88x%26%23178%3B-x%EF%BC%89%26%23178%3B-2%2B%E6%A0%B9%E5%8F%B73%E5%88%86%E4%B9%8Bx%26%23178%3B-x-1%E7%9A%84%E5%80%BC%E7%AD%89%E4%BA%8E%3F)
xN0_Aj8I oQd;v.m ETLBDgX(O-pKi>.wyR+vaޝz|@ݳŬݜ:yj-蟦^}N,cdg_l]$+ĭV(I7[ͬ$xdsIě(^c`p˾OA$$ \OXa%QDUX WB@=*ҾLSN
X/"(`Wء*c%,P7n3ű5{Oa 1ڸSPt'S'DY_X^a_%cLHfΤ5]{Ck"-F5 /o@
若x²-x-2=0,则(x²-x)²-2+根号3分之x²-x-1的值等于?
若x²-x-2=0,则(x²-x)²-2+根号3分之x²-x-1的值等于?
若x²-x-2=0,则(x²-x)²-2+根号3分之x²-x-1的值等于?
x^2-x=2
(x^2-x-1)/[(x^2-x)^2-2+✓3]
=1/(4-2+✓3)
=2-✓3
若x²-x-2=0,则x²-x=2,
(x²-x-1)/[(x²-x)²-2+√3]=(2-1)/(2²-2+√3)=1/(2+√3)=2-√3。