(1)3^2-1^2=8=8*1 (2)5^2-3^2=16=8*2 (3)7^2-5^2=24=8*3 (4)9^2-7^2=32=8*4 找出规律,将第n个式子表示出
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![(1)3^2-1^2=8=8*1 (2)5^2-3^2=16=8*2 (3)7^2-5^2=24=8*3 (4)9^2-7^2=32=8*4 找出规律,将第n个式子表示出](/uploads/image/z/327116-20-6.jpg?t=%281%293%5E2-1%5E2%3D8%3D8%2A1+%282%295%5E2-3%5E2%3D16%3D8%2A2+%283%297%5E2-5%5E2%3D24%3D8%2A3+%284%299%5E2-7%5E2%3D32%3D8%2A4+%E6%89%BE%E5%87%BA%E8%A7%84%E5%BE%8B%2C%E5%B0%86%E7%AC%ACn%E4%B8%AA%E5%BC%8F%E5%AD%90%E8%A1%A8%E7%A4%BA%E5%87%BA)
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(1)3^2-1^2=8=8*1 (2)5^2-3^2=16=8*2 (3)7^2-5^2=24=8*3 (4)9^2-7^2=32=8*4 找出规律,将第n个式子表示出
(1)3^2-1^2=8=8*1 (2)5^2-3^2=16=8*2 (3)7^2-5^2=24=8*3 (4)9^2-7^2=32=8*4 找出规律,将第n个式子表示出
(1)3^2-1^2=8=8*1 (2)5^2-3^2=16=8*2 (3)7^2-5^2=24=8*3 (4)9^2-7^2=32=8*4 找出规律,将第n个式子表示出
(2n+1)^2-(2n-1)^2=8n=8*n
1+2+1+1+1+2+3+8=几
3(x-1)^2-1=8
1-3/8-1/2=?
3(2^2+1)(2^4+1)(2^8+1)…(2^128+1)+1=?
(1+2+3)*8/56=0.78+?
x-3/8x=1/2
1+2+3+4、、、+8+9=
2+8+3+7+1+9=?
x-3+7-2+8+1=2x-1
1/2x-3+7-2+8=x-1
3*(2^2+1)(2^4+1)(2^8+1)(2^16+1)...(2^2n+1)+1=
81^1/2-(1/8)^-1+3^0=?
2x-1/6-3x-1/8=1
1+2-8=多少?
2/3+3/4x=1 5/8x+2/3×1/2=1
解方程2x-3/8=1-3/8
3/15+5/8+3/8+8/13= 12-(2/3-1/2)=
8+3=2,10+1=1求8+8=?