如题,(2x+1)²-(x+3)²-(x-1)²+1,

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如题,(2x+1)²-(x+3)²-(x-1)²+1,
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如题,(2x+1)²-(x+3)²-(x-1)²+1,
如题,(2x+1)²-(x+3)²-(x-1)²+1,

如题,(2x+1)²-(x+3)²-(x-1)²+1,
=(2x+1+x+3)(2x+1-x-3)+(1+x-1)(1-x+1)
=(3x+4)(x-2)+x(2-x)
=(3x+4-x)(x-2)
=2(x+2)(x-2)
=2x^2-8