解方程(x²+4x+4分之6x+12)+(x²-4x+4分之4-x²)=4-x²分之x²
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/31 21:54:18
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解方程(x²+4x+4分之6x+12)+(x²-4x+4分之4-x²)=4-x²分之x²
解方程(x²+4x+4分之6x+12)+(x²-4x+4分之4-x²)=4-x²分之x²
解方程(x²+4x+4分之6x+12)+(x²-4x+4分之4-x²)=4-x²分之x²
解方程(6x+12)/(x²+4x+4)+(4-x²)/(x²-4x+4)=x²/(4-x²)
6(x+2)/(x+2)²-(x+2)(x-2)/(x-2)²=-x²/(x²-4)
6/(x+2)-(x+2)/(x-2)+x²/(x+2)(x-2)=0
6(x-2)-(x+2)²+x²=0
2x-16=0
故x=8