已知4x-3y-6z=0,x+2y-7z=0,(xyz≠0),求(2x²+3y²+6z²)/(x²+5y²+7z²
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已知4x-3y-6z=0,x+2y-7z=0,(xyz≠0),求(2x²+3y²+6z²)/(x²+5y²+7z²
已知4x-3y-6z=0,x+2y-7z=0,(xyz≠0),求(2x²+3y²+6z²)/(x²+5y²+7z²
已知4x-3y-6z=0,x+2y-7z=0,(xyz≠0),求(2x²+3y²+6z²)/(x²+5y²+7z²
先把z看成已知数.前边两个方程相当于二元一次方程组,楼主应该会解的,得出x=3z,y=2z.把x=3z,y=2z代入后边的式子,上边是36倍的z的平方,下边也是36倍的z的平方,结果为1