解方程x²+x²分之1+2(x-x分之1)=1
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解方程x²+x²分之1+2(x-x分之1)=1
解方程x²+x²分之1+2(x-x分之1)=1
解方程x²+x²分之1+2(x-x分之1)=1
x²+1/x²=(x-1/x)²+2
所以,方程化为:(x-1/x)²+2+2(x-1/x)=1
即:(x-1/x)²+2(x-1/x)+1=0
[(x-1/x)+1]²=0
则:x-1/x=-1
x²-1=-x
x²+x-1=0
x=(-1±√5)/2
即:x1=(-1-√5)/2,x2=(-1+√5)/2