一电动机线圈的电阻为1Ω,线圈两端所加电压为2V时,电流为0.8A,电动机正常工作1.在求电动机正常工作1min所消耗的电能时,有一下两种不同的解法小明解:W=UIt=2V*0.8A*60S=96J小华解:W=I2Rt=(0.8A)2*1
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![一电动机线圈的电阻为1Ω,线圈两端所加电压为2V时,电流为0.8A,电动机正常工作1.在求电动机正常工作1min所消耗的电能时,有一下两种不同的解法小明解:W=UIt=2V*0.8A*60S=96J小华解:W=I2Rt=(0.8A)2*1](/uploads/image/z/3338654-14-4.jpg?t=%E4%B8%80%E7%94%B5%E5%8A%A8%E6%9C%BA%E7%BA%BF%E5%9C%88%E7%9A%84%E7%94%B5%E9%98%BB%E4%B8%BA1%CE%A9%2C%E7%BA%BF%E5%9C%88%E4%B8%A4%E7%AB%AF%E6%89%80%E5%8A%A0%E7%94%B5%E5%8E%8B%E4%B8%BA2V%E6%97%B6%2C%E7%94%B5%E6%B5%81%E4%B8%BA0.8A%2C%E7%94%B5%E5%8A%A8%E6%9C%BA%E6%AD%A3%E5%B8%B8%E5%B7%A5%E4%BD%9C1.%E5%9C%A8%E6%B1%82%E7%94%B5%E5%8A%A8%E6%9C%BA%E6%AD%A3%E5%B8%B8%E5%B7%A5%E4%BD%9C1min%E6%89%80%E6%B6%88%E8%80%97%E7%9A%84%E7%94%B5%E8%83%BD%E6%97%B6%2C%E6%9C%89%E4%B8%80%E4%B8%8B%E4%B8%A4%E7%A7%8D%E4%B8%8D%E5%90%8C%E7%9A%84%E8%A7%A3%E6%B3%95%E5%B0%8F%E6%98%8E%E8%A7%A3%EF%BC%9AW%3DUIt%3D2V%2A0.8A%2A60S%3D96J%E5%B0%8F%E5%8D%8E%E8%A7%A3%EF%BC%9AW%3DI2Rt%3D%280.8A%EF%BC%892%2A1)
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