若x²+2x+y²-8y+17=0 求x 的y次方的值~若x²+2x+y²-8y+17=0 求x 的y次方的值~
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若x²+2x+y²-8y+17=0 求x 的y次方的值~若x²+2x+y²-8y+17=0 求x 的y次方的值~
若x²+2x+y²-8y+17=0 求x 的y次方的值~
若x²+2x+y²-8y+17=0 求x 的y次方的值~
若x²+2x+y²-8y+17=0 求x 的y次方的值~若x²+2x+y²-8y+17=0 求x 的y次方的值~
由原式可知:X^2+2X+1+Y^2-8Y+16=0
即:(X+1)^2+(Y-4)^2=0
X+1=0,X=-1
Y-4=0,Y=4
所以X^Y=(-1)^4=1