已知m>n,且满足2m²+3m=1,2n²+3n=1,求m,n的值
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已知m>n,且满足2m²+3m=1,2n²+3n=1,求m,n的值
已知m>n,且满足2m²+3m=1,2n²+3n=1,求m,n的值
已知m>n,且满足2m²+3m=1,2n²+3n=1,求m,n的值
满足2m²+3m=1 ,2n²+3n=1
解 2x²+3x-1=0
得 X=-3+√17或-3-√17
又因为m>n
所以m=-3+√17,n=-3-√17
m,n为2x²+3x-1=0两根,又m>n,由求根公式·,m=(-3+根号17)÷4,n=(-3-根号17)÷4