作业帮若(cos2x)/[sin(x-π/4)]=（-根号2）/2,则cosx+sinx=?
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/28 19:13:06
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若(cos2x)/[sin(x-π/4)]=（-根号2）/2,则cosx+sinx=?
若(cos2x)/[sin(x-π/4)]=（-根号2）/2,则cosx+sinx=?
若(cos2x)/[sin(x-π/4)]=（-根号2）/2,则cosx+sinx=?
(cos2x)/[sin(x-π/4)]
=[(cosx)^2-(sinx)^2]/[((根号2)/2)sinx-((根号2)/2)cosx]
=(cosx-sinx)(cosx+sinx)/[-((根号2)/2)(cosx-sinx)]
=(cosx+sinx)/[-(根号2)/2]=-(根号2)/2,
所以 sinx+cosx= 1/2.