log12(27)=a,求log6(16),

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log12(27)=a,求log6(16),
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log12(27)=a,求log6(16),
log12(27)=a,求log6(16),

log12(27)=a,求log6(16),
log12(27)=a 可得:
lg27/lg12=a
3lg3/(2lg2+lg3)=a
可得:lg3=2alg2/(3-a)
log6(16)
=lg16/lg6
=4lg2/(lg2+lg3)
=4lg2/[lg2+2alg2/(3-a)]
=4(3-a)/(3+a)


a=log12(27)
=3log12(3)
=3/log3(12)
=3/[2log3(2)+1]
∴log3(2)=(3-a)/2a
log6(16)=log3(16)/log3(6)=4log3(2)/[log3(2)+1]=4(3-a)(3+a)