已知a b互为相反数,c d互为倒数,m的绝对值是2,若x=(2a+2b)/2+cd-1/2|m|,求x^2-1/4(1-3x/2)-1/3x(2-x/2)
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![已知a b互为相反数,c d互为倒数,m的绝对值是2,若x=(2a+2b)/2+cd-1/2|m|,求x^2-1/4(1-3x/2)-1/3x(2-x/2)](/uploads/image/z/3581714-2-4.jpg?t=%E5%B7%B2%E7%9F%A5a+b%E4%BA%92%E4%B8%BA%E7%9B%B8%E5%8F%8D%E6%95%B0%2Cc+d%E4%BA%92%E4%B8%BA%E5%80%92%E6%95%B0%2Cm%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%E6%98%AF2%2C%E8%8B%A5x%3D%282a%2B2b%29%2F2%2Bcd-1%2F2%7Cm%7C%2C%E6%B1%82x%5E2-1%2F4%281-3x%2F2%29-1%2F3x%282-x%2F2%29)
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已知a b互为相反数,c d互为倒数,m的绝对值是2,若x=(2a+2b)/2+cd-1/2|m|,求x^2-1/4(1-3x/2)-1/3x(2-x/2)
已知a b互为相反数,c d互为倒数,m的绝对值是2,若x=(2a+2b)/2+cd-1/2|m|,求x^2-1/4(1-3x/2)-1/3x(2-x/2)
已知a b互为相反数,c d互为倒数,m的绝对值是2,若x=(2a+2b)/2+cd-1/2|m|,求x^2-1/4(1-3x/2)-1/3x(2-x/2)
因为a b互为相反数,c d互为倒数
所以a+b=0,cd=1
x=(2a+2b)/2+cd-1/2|m|
=a+b+cd-1/2|m|
=0+1-1/2*2
=1-1
=0
x^2-1/4(1-3x/2)-1/3x(2-x/2)
=0^2-1/4*(1-0)-0*(2-0/2)
=-1/4