化简sin(啊尔法+贝塔)cos啊尔法-1/2[sin(2啊尔法+贝塔)-sin贝塔]
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/06 07:05:47
x){3]8E39.ko
ReL(a$SD;Zϧl
qnMt:fP&|nD-~=`qs&
$@l$,XLӆ> bzAXV"_\gJR j
化简sin(啊尔法+贝塔)cos啊尔法-1/2[sin(2啊尔法+贝塔)-sin贝塔]
化简sin(啊尔法+贝塔)cos啊尔法-1/2[sin(2啊尔法+贝塔)-sin贝塔]
化简sin(啊尔法+贝塔)cos啊尔法-1/2[sin(2啊尔法+贝塔)-sin贝塔]
解由sin(α+β)cosα-1/2[sin(2α+β)-sinβ]
=sin(α+β)cosα-1/2[sin(α+β+α)-sinβ]
=sin(α+β)cosα-1/2[sin(α+β+α)-sinβ]
=sin(α+β)cosα-1/2[sin(α+β)cosα+cos(α+β)sinα-sinβ]
=sin(α+β)cosα-1/2sin(α+β)cosα-1/2cos(α+β)sinα+1/2sinβ
=1/2sin(α+β)cosα-1/2cos(α+β)sinα+1/2sinβ
=1/2[sin(α+β)cosα-cos(α+β)sinα]+1/2sinβ
=1/2sin(α+β-β)+1/2sinβ
=1/2sin(α)+1/2sinβ
化简sin(啊尔法+贝塔)cos啊尔法-1/2[sin(2啊尔法+贝塔)-sin贝塔]
cos x/sin x+sin x/(1+cos x) 化简.
化简sin a+cos a
sin^2cos^2化简
sinα+cosα 化简
化简:1+sinθ+cosθ+2sinθcosθ /1+sinθ+cosθ
(化简):[sin(派-啊而法)*sin( (3派/2)-啊尔法)*tan(-啊尔法-派)] / cot(啊尔法-2派)*cot( (3派/2)+啊尔法)*cos( (派/2)+啊尔法)
sin cos
化简 (1-2sin@cos@)/(cos@^2-sin@^2)*(1+2sin@cos@)/(1-2sin@^2) 两分式相乘
求值:已知sin啊尔法-2cos啊尔法=0,求sin(拍-啊尔法)cos(2拍-啊尔法)sin[-啊尔法+(3拍/2)/tan(-啊尔法-...求值:已知sin啊尔法-2cos啊尔法=0,求sin(拍-啊尔法)cos(2拍-啊尔法)sin[-啊尔法+(3拍/2)/tan(-啊尔法-拍)s
化简tan a(cos a-sin a)+sin a(sin a+tan a)/1+cos a
化简:tanα(cosα-sinα)+sinα(sinα+tanα)/1+cosα.
化简(sin x+cos x-1)(sin x-cos x+1)/sin 2x
化简COS(a+B)COS(a-B)+sin平方B
cos(α+β)cos(α-β)+sin²β 化简
化简(sin²α/1-cosα)-cosα
化简cos(a+b)cos(a-b)+sin^2b
化简sin(x)cos(x)cos(2x)