已知数列{an}的前n项和是Sn(n是N*),a1=2/3,n>1,SnSn-1-3Sn+2=0求,Bn=1/(Sn-1)(Bn)的通项公式?我不知怎样解,我希望帮我解出来.
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![已知数列{an}的前n项和是Sn(n是N*),a1=2/3,n>1,SnSn-1-3Sn+2=0求,Bn=1/(Sn-1)(Bn)的通项公式?我不知怎样解,我希望帮我解出来.](/uploads/image/z/3621924-36-4.jpg?t=%E5%B7%B2%E7%9F%A5%E6%95%B0%E5%88%97%7Ban%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8C%E6%98%AFSn%28n%E6%98%AFN%2A%29%2Ca1%3D2%2F3%2Cn%3E1%2CSnSn-1-3Sn%2B2%3D0%E6%B1%82%2CBn%3D1%2F%28Sn-1%29%28Bn%29%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%3F%E6%88%91%E4%B8%8D%E7%9F%A5%E6%80%8E%E6%A0%B7%E8%A7%A3%2C%E6%88%91%E5%B8%8C%E6%9C%9B%E5%B8%AE%E6%88%91%E8%A7%A3%E5%87%BA%E6%9D%A5.)
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