将数列{2^n}依次按1项、2项、3项、4项循环地分为(a1),(a2,a3),(a4,a5,a6),(a7,a8,a9,a10);(a11),(a12,a13),(a14,a15,a16),(a17,a18,a19,a20),(a21),…,分别计算各个括号内各数之和,设由这些和按原来括号的前后顺序构
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![将数列{2^n}依次按1项、2项、3项、4项循环地分为(a1),(a2,a3),(a4,a5,a6),(a7,a8,a9,a10);(a11),(a12,a13),(a14,a15,a16),(a17,a18,a19,a20),(a21),…,分别计算各个括号内各数之和,设由这些和按原来括号的前后顺序构](/uploads/image/z/362733-69-3.jpg?t=%E5%B0%86%E6%95%B0%E5%88%97%7B2%5En%7D%E4%BE%9D%E6%AC%A1%E6%8C%891%E9%A1%B9%E3%80%812%E9%A1%B9%E3%80%813%E9%A1%B9%E3%80%814%E9%A1%B9%E5%BE%AA%E7%8E%AF%E5%9C%B0%E5%88%86%E4%B8%BA%28a1%29%2C%28a2%2Ca3%29%2C%28a4%2Ca5%2Ca6%29%2C%28a7%2Ca8%2Ca9%2Ca10%29%EF%BC%9B%28a11%29%2C%28a12%2Ca13%29%2C%28a14%2Ca15%2Ca16%29%2C%28a17%2Ca18%2Ca19%2Ca20%29%2C%28a21%29%2C%E2%80%A6%2C%E5%88%86%E5%88%AB%E8%AE%A1%E7%AE%97%E5%90%84%E4%B8%AA%E6%8B%AC%E5%8F%B7%E5%86%85%E5%90%84%E6%95%B0%E4%B9%8B%E5%92%8C%2C%E8%AE%BE%E7%94%B1%E8%BF%99%E4%BA%9B%E5%92%8C%E6%8C%89%E5%8E%9F%E6%9D%A5%E6%8B%AC%E5%8F%B7%E7%9A%84%E5%89%8D%E5%90%8E%E9%A1%BA%E5%BA%8F%E6%9E%84)
将数列{2^n}依次按1项、2项、3项、4项循环地分为(a1),(a2,a3),(a4,a5,a6),(a7,a8,a9,a10);(a11),(a12,a13),(a14,a15,a16),(a17,a18,a19,a20),(a21),…,分别计算各个括号内各数之和,设由这些和按原来括号的前后顺序构
将数列{2^n}依次按1项、2项、3项、4项循环地分为(a1),(a2,a3),(a4,a5,a6),(a7,a8,a9,a10);(a11),(a12,a13),(a14,a15,a16),(a17,a18,a19,a20),(a21),…,分别计算各个括号内各数之和,设由这些和按原来括号的前后顺序构成的数列为{bn},则b5+b100的值为_________.
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将数列{2^n}依次按1项、2项、3项、4项循环地分为(a1),(a2,a3),(a4,a5,a6),(a7,a8,a9,a10);(a11),(a12,a13),(a14,a15,a16),(a17,a18,a19,a20),(a21),…,分别计算各个括号内各数之和,设由这些和按原来括号的前后顺序构
b1=2 b2=12 b3=112 b4=1920
b5=2*2^10 b6=12*2^10 b7=112*2^10 b8=1920*2^10
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b(4k+1)=2*(2^10)^k b(4k+2)=12*(2^10)^k
b(4k+3)=112*(2^10)^k b(4k+4)=1920*(2^10)^k
b5=2*2^10=2^11
b100=1920*(2^10)^24=15*2^7*2^240=15*2^247
b5+b100=2^11+15*2^247