x+9+z=100 3x+2y+0.5z=100 2x=y
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x+9+z=100 3x+2y+0.5z=100 2x=y
x+9+z=100 3x+2y+0.5z=100 2x=y
x+9+z=100 3x+2y+0.5z=100 2x=y
整理:x+z=91 6x+4y+z=200 2x=y
2式减去1式:5x+4y=109
和3式解出:x=109/13 y=218/13 z=1074/13
x+9y+z=100 a
3x+2y+0.5z=100 b
2x=y c
将c代入a.b
19x+z=100 d
7x+0.5z=100 e
e*2-d
-5x=100
x=-20
y=2x=-40
z=100+380=480
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
x+9+z=100 3x+2y+0.5z=100 2x=y
x+9+z=100 3x+2y+0.5z=100 2x=y
证明 :x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0
x/2=y/3=z/5 x+3y-z/x-3y+z
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
若x+y+z=3y=2z,则x/x+y+z=?
三元一次方程x+y+z=0 4x+2y+z=3 9x+3y+z=6x+y+z=04x+2y+z=3 9x+3y+z=6
解方程 x+y+z=0 4x+2y+z=3 9x-3y+z=28解方程x+y+z=04x+2y+z=39x-3y+z=28
x+y=5 2x+3y-z=9 x-y+z=4
三元一次方程 X+Y-Z=0.5 X-3Y+2Z 3X+2Y-Z=2
2x+y-z=2 x-y+2z=2 3x+2y+4z=9
2x+y-z=2 x-y+2z=2 3x+2y+4z=9
3x+2y+z=9,x+y+2z=0,2x+3y-z=11