已知2x+y=7,x^2+y^2=5,求(4x+2y)^2-3x^2-y^2+2(1-y^2)的值
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已知2x+y=7,x^2+y^2=5,求(4x+2y)^2-3x^2-y^2+2(1-y^2)的值
已知2x+y=7,x^2+y^2=5,求(4x+2y)^2-3x^2-y^2+2(1-y^2)的值
已知2x+y=7,x^2+y^2=5,求(4x+2y)^2-3x^2-y^2+2(1-y^2)的值
(4x+2y)^2-3x^2-y^2+2(1-y^2)
=[2(2x+y)]²-3(x²+y²)+2
=(2×7)²-3×5+2
=183
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