作业帮初二数学!先化简在求值
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/29 07:02:10
x]OP ƿ@@ӱHǍޘ cU*^my `b`0TА8F^ pG
m$p>9?F\s.u~EQ)dUF4Ztb"gxBC[4MڛwM!sPN4 4# J"i >4EJs R gjzǐ $' E:'
$ '(C
I0 $%8`U;uvx]b.@PcD"qEQX7 aUwyr\p;l ɷu8Yy> ?'Y*PA6U`1їD9N^._Y?$r!U /`~E:1VYGE`N슳2V8va/U.Kga2융8[ne.="t|
wEP۳Y4=#\d
mH={o# u>yg/^M0,r ;S2=nCswN1k/휕W0P;{tk.Y'kNiZ`}} P~'և^/46&ezTت
初二数学!先化简在求值
初二数学!先化简在求值
初二数学!先化简在求值
=1/(x+1) -(x+3)/(x+1)(x-1) ×(x-1)²/(x+3)(x+1)
=1/(x+1) -(x-1)/(x+1)²
=(x+1)/(x+1)²-(x-1)/(x+1)²
=[(x+1)-(x-1)]/(x+1)²
=2/(x+1)²
当x=-3时
原式=2/(-3+1)²=1/2
先乘除后加减，你之前做的顺序有问题
再有最后一个分式要记得因式分解啊
原式=1/(x+1)-(x+3)/(x+1)(x-1)*(x-1)²/(x+1)(x+3)
=(x+1)/(x+1)²-(x-1)/(x+1)²
=(x+1-x+1)/(x+1)²
=2/(x+1)²
=2/(-3+1)²
=1/2
点击[http://pinyin.cn/1ISnbyLoMWZ] 查看这张图片。[访问验证码是：919184请妥善保管]
1/(x+1)-(x+3)/(x^2-1)÷(x^2+4x+3)/(x^2-2x+1)
=1/(x+1)-(x+3)/(x^2-1)X(x-1)^2/(x+1)(x+3)
=1/(x+1)-(x-1)/(x+1)^2
=(x+1-x+1)/(x+1)^2
=2/(x+1)^2
X=-3
原式=1/2