已知三角形ABC的三个顶点A(2,8)B(-4,0)C(6,0)则AB边上的中线CD所在直线的方程为
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![已知三角形ABC的三个顶点A(2,8)B(-4,0)C(6,0)则AB边上的中线CD所在直线的方程为](/uploads/image/z/3653324-44-4.jpg?t=%E5%B7%B2%E7%9F%A5%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E4%B8%89%E4%B8%AA%E9%A1%B6%E7%82%B9A%282%2C8%29B%28-4%2C0%29C%286%2C0%29%E5%88%99AB%E8%BE%B9%E4%B8%8A%E7%9A%84%E4%B8%AD%E7%BA%BFCD%E6%89%80%E5%9C%A8%E7%9B%B4%E7%BA%BF%E7%9A%84%E6%96%B9%E7%A8%8B%E4%B8%BA)
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