a²-b²/a³+b³÷a²-2ab+b²/a²-ab+b²乘1/(b-a)²
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a²-b²/a³+b³÷a²-2ab+b²/a²-ab+b²乘1/(b-a)²
a²-b²/a³+b³÷a²-2ab+b²/a²-ab+b²乘1/(b-a)²
a²-b²/a³+b³÷a²-2ab+b²/a²-ab+b²乘1/(b-a)²
原式=(a+b)(a-b)/[(a+b)(a²-ab+b²)]÷[(a-b)²/(a²-ab+b²)]×[1/(a-b)²]
=[(a-b)/(a²-ab+b²)]×[(a²-ab+b²)/(a-b)²]×[1/(a-b)²]
=1/(a-b)³