计算(lg√27+lg8-lg√1000)/lg1.2.lg1.2=lg12-1?
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/12 00:46:30
![计算(lg√27+lg8-lg√1000)/lg1.2.lg1.2=lg12-1?](/uploads/image/z/3690244-28-4.jpg?t=%E8%AE%A1%E7%AE%97%28lg%E2%88%9A27%2Blg8-lg%E2%88%9A1000%29%2Flg1.2.lg1.2%3Dlg12-1%EF%BC%9F)
x){nu5ru22I
4s
-45|gMR>Q
5ِo-^`tkٚS4!*B y#!vYC26yv _ k{
计算(lg√27+lg8-lg√1000)/lg1.2.lg1.2=lg12-1?
计算(lg√27+lg8-lg√1000)/lg1.2.
lg1.2=lg12-1?
计算(lg√27+lg8-lg√1000)/lg1.2.lg1.2=lg12-1?
(lg√27+lg8-lg√1000)/lg1.2
=(3/2lg3+3lg2-3/2)/(lg12-1)
=3/2(lg3+2lg2-1)/(lg12-1)
=3/2(lg12-1)/(lg12-1)
=3/2