数学圆的方程设O为坐标原点,曲线X²+Y²+2X-6Y+1=0上有两点P、Q,满足关于直线X-Y+4=0对称,又满足OP·OQ=0 (OP和OQ为向量)求直线PQ的方程答案是Y=-X+1不是Y=-x+2啊!
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![数学圆的方程设O为坐标原点,曲线X²+Y²+2X-6Y+1=0上有两点P、Q,满足关于直线X-Y+4=0对称,又满足OP·OQ=0 (OP和OQ为向量)求直线PQ的方程答案是Y=-X+1不是Y=-x+2啊!](/uploads/image/z/3691379-11-9.jpg?t=%E6%95%B0%E5%AD%A6%E5%9C%86%E7%9A%84%E6%96%B9%E7%A8%8B%E8%AE%BEO%E4%B8%BA%E5%9D%90%E6%A0%87%E5%8E%9F%E7%82%B9%2C%E6%9B%B2%E7%BA%BFX%26sup2%3B%2BY%26sup2%3B%2B2X-6Y%2B1%3D0%E4%B8%8A%E6%9C%89%E4%B8%A4%E7%82%B9P%E3%80%81Q%2C%E6%BB%A1%E8%B6%B3%E5%85%B3%E4%BA%8E%E7%9B%B4%E7%BA%BFX-Y%2B4%3D0%E5%AF%B9%E7%A7%B0%2C%E5%8F%88%E6%BB%A1%E8%B6%B3OP%C2%B7OQ%3D0+%EF%BC%88OP%E5%92%8COQ%E4%B8%BA%E5%90%91%E9%87%8F%EF%BC%89%E6%B1%82%E7%9B%B4%E7%BA%BFPQ%E7%9A%84%E6%96%B9%E7%A8%8B%E7%AD%94%E6%A1%88%E6%98%AFY%3D-X%2B1%E4%B8%8D%E6%98%AFY%3D-x%2B2%E5%95%8A%EF%BC%81)
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