求下列函数的定义域y=8次根号下log2(x) y=根号下log0.5(4x-3) y=(根号下x^2-x+1 ) +log2(3x)
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/01 14:33:20
![求下列函数的定义域y=8次根号下log2(x) y=根号下log0.5(4x-3) y=(根号下x^2-x+1 ) +log2(3x)](/uploads/image/z/3695875-43-5.jpg?t=%E6%B1%82%E4%B8%8B%E5%88%97%E5%87%BD%E6%95%B0%E7%9A%84%E5%AE%9A%E4%B9%89%E5%9F%9Fy%3D8%E6%AC%A1%E6%A0%B9%E5%8F%B7%E4%B8%8Blog2%EF%BC%88x%EF%BC%89+y%3D%E6%A0%B9%E5%8F%B7%E4%B8%8Blog0.5%284x-3%29+y%3D%28%E6%A0%B9%E5%8F%B7%E4%B8%8Bx%5E2-x%2B1+%29+%2Blog2%283x%29)
x){Ɏӟ}6uY-Oz,|`@59FtTөPi,lgaRk ׀KTVh*h*hjWh$F;m@MYڰe.YdW@YgÓKTh>\j
F
+1xgs}MB >Xԅ
OvL1zm勁l<;PP 3o
求下列函数的定义域y=8次根号下log2(x) y=根号下log0.5(4x-3) y=(根号下x^2-x+1 ) +log2(3x)
求下列函数的定义域y=8次根号下log2(x) y=根号下log0.5(4x-3) y=(根号下x^2-x+1 ) +log2(3x)
求下列函数的定义域y=8次根号下log2(x) y=根号下log0.5(4x-3) y=(根号下x^2-x+1 ) +log2(3x)
偶数次根号下的值都要大于等于0所以
1 log2(x)≥0,所以x≥1
2 log0.5(4x-3)≥0,0<4x-3≤1 得 3/4<x≤1
3 x^2-x+1≥0 且3x>0 解得x>0