作业帮cos(xy)=x求隐函数的导数dy/dx
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cos(xy)=x求隐函数的导数dy/dx
cos(xy)=x求隐函数的导数dy/dx
cos(xy)=x求隐函数的导数dy/dx
cos(xy)=x
两边对x求导：-sin(xy)[y+xy']=1
y+xy'=-1/sin(xy)
xy'=-y-(1/sin(xy))
y'=[-y-(1/sin(xy))]/x
cos(xy)=x.关于x求导：[-sin(xy)]×(y+xy′)=1.===>y+xy′=-1/sin(xy).===>xy'=-y-[1/sin(xy)].===>y'={-y-[1/sin(xy)]}/x.∴(dy)/(dx)=-{y+[1/sin(xy)]}/x
cos(xy)=x
dcos(xy)/d(xy)*d(xy)/dx=dx/dx
-sin(xy)*[y*dx/dx+x*dy/dx]=1
y+x*dy/dx=-csc(xy)
x*dy/dx=-csc(xy)-y
dy/dx=-[y+csc(xy)]/x
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