已知x²-2x-1=0,求(1)x²+1/x²、 (2)x²/x的四次方+x²+1的值急!求大神老师解答
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已知x²-2x-1=0,求(1)x²+1/x²、 (2)x²/x的四次方+x²+1的值急!求大神老师解答
已知x²-2x-1=0,求(1)x²+1/x²、 (2)x²/x的四次方+x²+1的值
急!求大神老师解答
已知x²-2x-1=0,求(1)x²+1/x²、 (2)x²/x的四次方+x²+1的值急!求大神老师解答
x²-2x-1=0
除以x得 x-2-1/x=0
∴x-1/x=2
(1)x²+1/x²
=(x-1/x)²+2
=2²+2
=6
(2) (x的四次方+x²+1﹚÷x²
=x²+1+1/x²
=6+1
=7
∴x²/x的四次方+x²+1=1/7