已知x²+5y²-4xy+2y+1=0,求2x-y的值
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已知x²+5y²-4xy+2y+1=0,求2x-y的值
已知x²+5y²-4xy+2y+1=0,求2x-y的值
已知x²+5y²-4xy+2y+1=0,求2x-y的值
(x²-4xy+4y²)+(y²+2y+1)=0
(x-2y)²+(y+1)²=0
所以:
x-2y=0
y+1=0
解得:
x=-2
y=-1
2x-y
=2×(-2)+1
=-3