若(x²+y²)(x²+y²-1)-2=0,求x²+y²的值
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若(x²+y²)(x²+y²-1)-2=0,求x²+y²的值
若(x²+y²)(x²+y²-1)-2=0,求x²+y²的值
若(x²+y²)(x²+y²-1)-2=0,求x²+y²的值
令x²+y²=a (a≥0)
原式变为
a(a-1)-2=0
a^2-a-2=0
(a-2)(a+1)=0
a1=2,a2=-1(舍去)
∴a=2
即x^2+y^2=2