已知方程x²-6x+9=0可以配方成(x-p)²=7的形式,那x²-6x+9=2可以配成下列的那种形式,为什么A,(x-p)²=5 B,(x-p)²=9 C,(x-9+2)²=9 D,(x-p+2) ²=5
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![已知方程x²-6x+9=0可以配方成(x-p)²=7的形式,那x²-6x+9=2可以配成下列的那种形式,为什么A,(x-p)²=5 B,(x-p)²=9 C,(x-9+2)²=9 D,(x-p+2) ²=5](/uploads/image/z/3704231-47-1.jpg?t=%E5%B7%B2%E7%9F%A5%E6%96%B9%E7%A8%8Bx%26%23178%3B-6x%2B9%3D0%E5%8F%AF%E4%BB%A5%E9%85%8D%E6%96%B9%E6%88%90%28x-p%29%26%23178%3B%3D7%E7%9A%84%E5%BD%A2%E5%BC%8F%2C%E9%82%A3x%26%23178%3B-6x%2B9%3D2%E5%8F%AF%E4%BB%A5%E9%85%8D%E6%88%90%E4%B8%8B%E5%88%97%E7%9A%84%E9%82%A3%E7%A7%8D%E5%BD%A2%E5%BC%8F%2C%E4%B8%BA%E4%BB%80%E4%B9%88A%2C%28x-p%29%26%23178%3B%3D5+B%2C%28x-p%29%26%23178%3B%3D9+C%2C%28x-9%2B2%29%26%23178%3B%3D9+D%2C%28x-p%2B2%29+%26%23178%3B%3D5)
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已知方程x²-6x+9=0可以配方成(x-p)²=7的形式,那x²-6x+9=2可以配成下列的那种形式,为什么A,(x-p)²=5 B,(x-p)²=9 C,(x-9+2)²=9 D,(x-p+2) ²=5
已知方程x²-6x+9=0可以配方成(x-p)²=7的形式,那x²-6x+9=2可以配成下列的那种形式,为什么
A,(x-p)²=5 B,(x-p)²=9 C,(x-9+2)²=9 D,(x-p+2) ²=5
已知方程x²-6x+9=0可以配方成(x-p)²=7的形式,那x²-6x+9=2可以配成下列的那种形式,为什么A,(x-p)²=5 B,(x-p)²=9 C,(x-9+2)²=9 D,(x-p+2) ²=5
x²-6x+9=0
(x-p)²=7
x²-6x+16=(x-p)²
x²-6x+9=2
x²-6x+16=2+7
(x-p)²=9
选B
x²-6x+9=0
(x-p)²=7
即
(x-p)²-7=0
即
x²-6x+9=(x-p)²-7 (1)
x²-6x+9=2
即
x²-6x+9-2=0
(1)代入
(x-p)²-7-2=0
(x-p)²=9
选B
证明:
∵(x-p)²=7
∴(x-p)²-7=0
又∵x²-6x+9=0
∴x²-6x+9=(x-p)²-7
把x²-6x+9=2代入x²-6x+9=(x-p)²-7
∴ 2=(x-p)²-7
∴(x-p)²-7-2=0
∴(x-p)²=9
选B