点p是椭圆x2/5+y2/4=1上一点,以点p以及焦点f1,f2为顶点的三角形的面积等于1,求点pF1坐标(-C,0).F2(C,0).根据椭圆性质:a^2=b^2+c^2..由x2/5+y2/4=1可知道..a^2=5,b^2=4推出..c^2=1..“以点p以及焦点f1,f2为顶点的
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/31 10:03:26
![点p是椭圆x2/5+y2/4=1上一点,以点p以及焦点f1,f2为顶点的三角形的面积等于1,求点pF1坐标(-C,0).F2(C,0).根据椭圆性质:a^2=b^2+c^2..由x2/5+y2/4=1可知道..a^2=5,b^2=4推出..c^2=1..“以点p以及焦点f1,f2为顶点的](/uploads/image/z/3704397-69-7.jpg?t=%E7%82%B9p%E6%98%AF%E6%A4%AD%E5%9C%86x2%2F5%2By2%2F4%3D1%E4%B8%8A%E4%B8%80%E7%82%B9%2C%E4%BB%A5%E7%82%B9p%E4%BB%A5%E5%8F%8A%E7%84%A6%E7%82%B9f1%2Cf2%E4%B8%BA%E9%A1%B6%E7%82%B9%E7%9A%84%E4%B8%89%E8%A7%92%E5%BD%A2%E7%9A%84%E9%9D%A2%E7%A7%AF%E7%AD%89%E4%BA%8E1%2C%E6%B1%82%E7%82%B9pF1%E5%9D%90%E6%A0%87%28-C%2C0%29.F2%28C%2C0%29.%E6%A0%B9%E6%8D%AE%E6%A4%AD%E5%9C%86%E6%80%A7%E8%B4%A8%3Aa%5E2%3Db%5E2%2Bc%5E2..%E7%94%B1x2%2F5%2By2%2F4%3D1%E5%8F%AF%E7%9F%A5%E9%81%93..a%5E2%3D5%2Cb%5E2%3D4%E6%8E%A8%E5%87%BA..c%5E2%3D1..%E2%80%9C%E4%BB%A5%E7%82%B9p%E4%BB%A5%E5%8F%8A%E7%84%A6%E7%82%B9f1%2Cf2%E4%B8%BA%E9%A1%B6%E7%82%B9%E7%9A%84)
xR;OA+GX
4jlHm4
j'(ܝanwsw`-ffoQ2q33ͯoYucʱ**-WDA6, 2qMzKlM*;9VibMF%slyhMSTK|b,*!Mguwmc*NR,߲Q+sKo5 :q_6 P5
ӭ30J%۷{a.bp&Ǡo@1!ܐTa>ܕHL}7wl6+r&}s )I, #V