已知f(z+i)=z+2z-2i,则f(i)=?
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已知f(z+i)=z+2z-2i,则f(i)=?
已知f(z+i)=z+2z-2i,则f(i)=?
已知f(z+i)=z+2z-2i,则f(i)=?
f(z+i)=z+2z-2i,则f(i)=?
f(z+i)=z+2z-2i,
令z=0,有:
f(i)=-2i
已知f(z+i)=z+2z-2i,则f(i)=?
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