已知|(x+y)2-4|+[(x-y)2-3]2+0,求x2+y2和xy的值

来源：学生作业帮助网 编辑：作业帮 时间：2024/11/06 09:30:09
已知|(x+y)2-4|+[(x-y)2-3]2+0,求x2+y2和xy的值
xJ1_e@,$&"‰h"r >q0dY|/GwxWRWVXCy$h9y:o/>>xMLiPm   0TEPhK H!Qց0Ĉ"mح(ԉLyBnl 4&ۧկ7_LQ8^ULjkSF]~uFAh&䔁Ekc68|9<8/A

已知|(x+y)2-4|+[(x-y)2-3]2+0,求x2+y2和xy的值
已知|(x+y)2-4|+[(x-y)2-3]2+0,求x2+y2和xy的值

已知|(x+y)2-4|+[(x-y)2-3]2+0,求x2+y2和xy的值
|(x+y)2-4|+[(x-y)2-3]2=0
=>(x+y)^2-4 =0 and (x-y)^2-3 =0
=>(x+y)^2 = 4 (1) and
(x-y)^2 = 3 (2)
(1) -(2)
4xy =1
xy =1/4
(1)+(2)
2(x^2+y^2) =7
x^2+y^2 = 7/2

题目写错了吧

(x+y)²=4
x²+y²+2xy=4 (1)
(x-y)²=3
x²+y²-2xy=3 (2)
(1)+(2),
x²+y²=7/2
(1)-(2),
xy=1/4

已知2y-x=-3,求[4y(2x-y)-2x(2x-y)]/(2x-y 已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y² 已知x*x+4x+y*y-2y+5=0,则x*x+y*y=? 已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值? 已知:【(x²+y²)-(x-y)²+2y(x-y)】/4y=1,求4x/4x²-y²-1/2x+y 已知x-y=1,求[(x+2y)^2+(2x+y)(x-4y)-3(x+y)(x-y)]除以y的值大神们帮帮忙 已知x-y=1,求[(x+2y)²+(2x+y)(x-4y)-3(x+y)(x-y)]÷y的值 已知(x+2y)(2x-3y)=y(y-4x),试求x/y的值 已知x=3分之一,y=-2分之一,求代数式x-(x+y)+(x+2Y)-(x+3y)+(x+4y)...-(x+2009y) 已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y) 已知x=y+2,求[(x+y)(x-y)-(x-y)的2次方+2y(x-y)]÷4y的值 已知x^2+y^2+13-4x+6y=0,求(2x-y)^2-2(2x-y)(x+2y)+(x+2y)^2 已知2x-y除以x+y等于2,求代数式(4x-2y除以x+y)-(4x+4y除以2x-y)的值 已知2x-y分之x+y=2,求代数式4x-2y分之x+y-4x+4y分之2x-y的值 已知(2x-y)/(x+y)=2,求代数式(4x-2y)/(x+y)-(4x+4y)/(2x-y)的值. 已知(2x-y)/(x+y)=2,求代数式(4x-2y)/(x+y)-(4x+4y)/(2x-y)的值 x+y分之4x-2y减2x-y分之4x+4y 已知x+y分之2x-y=2 已知2x-y/x+3y=2,求代数式4x-2y/x+3y减4x+12y除以2x-y