作业帮化简(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x)
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/27 19:21:45
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化简(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x)
化简(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x)
化简(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x)
(sin^2x-cos^4x+cos^2x-sin^4x)/(sin^2x-cos^6x+cos^2x-sin^6x)
=[sinx^2(1-sinx^2)+cosx^2(1-cosx^2)]/[sinx^2(1-sinx^4)+cosx^2(1-cosx^4)]
=2sinx^2cosx^2/[3*sinx^2cosx^2]
=2/3
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