x²-2(x²-3xy)+3(y²-2xy)-2y²,其中x、y满足:2x-1的绝对值+(y+1)²=0.
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x²-2(x²-3xy)+3(y²-2xy)-2y²,其中x、y满足:2x-1的绝对值+(y+1)²=0.
x²-2(x²-3xy)+3(y²-2xy)-2y²,其中x、y满足:2x-1的绝对值+(y+1)²=0.
x²-2(x²-3xy)+3(y²-2xy)-2y²,其中x、y满足:2x-1的绝对值+(y+1)²=0.
2x-1的绝对值+(y+1)²=0
∴﹛2x-1=0
y+1=0
∴x=1/2,y=-1
x²-2(x²-3xy)+3(y²-2xy)-2y²
=x²-2x²+6xy+3y²-6xy-2y²
=-x²+y²
=-(1/2)²+(-1)²
=3/4