函数y=sin(π/4-3x)+√3cos(π/4-3x)的最小正周期为?
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函数y=sin(π/4-3x)+√3cos(π/4-3x)的最小正周期为?
函数y=sin(π/4-3x)+√3cos(π/4-3x)的最小正周期为?
函数y=sin(π/4-3x)+√3cos(π/4-3x)的最小正周期为?
y=sin(π/4-3x)+√3cos(π/4-3x)=2sin(π/4-3x+π/3)=2sin(7π/12-3x)=2sin(π-7π/12+3x)
=2sin(3x+5π/12)
故T=2π/3
=2sin(π/4-3x+π/3)
=2sin(7π/12-3x)
T=π/3