sinπ,sinπ/2,sin3π/2,cosπ/2,cos-π/2,cos/2π/3 等等一系列怎么算最好能把一个周期的结果都发给我谢谢了

求值:2sinπ/6+sin3π/2-2cosπ+2sinπ/3 (sinπ/12)-(sin5π/12)+(2sinπ/8)(sin3π/8) sinπ/12-sin5π/12+2sinπ/8sin3π/8 sinπ/6,sin1,sin3较大小[cos2=sin(π/2-2)] 已知sinα+sinβ=根号3(cosβ-cosα),α,β∈(0,π/2),求证：sin3α+sin3β=0 n大于等于1,θ不是π的倍数,求证sinθ+sin3θ+...+sin((2n-1)θ)=sin^2(nθ)/sinθ 化简 (1)、sin(α+180度)cos(-α)sin(-α-180度) (2)、sin3(-α)cos(2π+α)tan(- sin3/7π*cos2/5π-cos(-3/7π)*sin(-2/5π) sinπ /14*sin3π /14*sin5π /14 sin6分之π+sin3分之π+sin2分之π+sin3分之2π+sin6分之5π+sinπ的值 比较大小:sinπ/5,sin3π/5 求证sin3*sin1=sin^2(2)-sin^2(1) sin3π/2= 计算sin^2 (π/4)-cos^2 (π/4) * cosπ+3/4π^2 (π/6)+sin3π/2 cosπ/3+tanπ/4+3tan²π/6+sinπ/2+cosπ+sin3π/2等于?. sin3π/4=,sin11π/4=,sin7π/4=,sin-1π/2=,sin-1π/4= cos7π/3-sin^2(17π/4)-1/3tan^2(π/3)sin3π/2+cos0=? 若sin(π-a)=1/2+cosa,则sin3次方(π+a)+cos3次方(2π-a)=