4b²c²-(c²+b²)²
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4b²c²-(c²+b²)²
4b²c²-(c²+b²)²
4b²c²-(c²+b²)²
4b²c²-(c²+b²)²
=(2bc)²-(c²+b²)²
=(2bc+c²+b²)[2bc-(c²+b²)]
=(b+c)²[-(c²+b²-2bc)]
=-(b+c)²(b-c)²
4b²c²-(c²+b²)²
=4b²c²-(c的四次方+2c²b²+b的四次方)
=2b²c²+c的四次方+b的四次方
=b²c²(2+c²+b²)
4b²c²-(c²+b²)²=(2bc)²-(c²+b²)²=(2bc+ c²+b² )x (2bc - c²+b² )=( c+b )²x( c-b )²=)=[( c+b )x( c-b )]²=[c²-b²]²=c的4次方加b的4次方减去2倍b²乘以c²