已知抛物线Y=ax2+bx+c的顶点C(1,—2),与X轴交于A,B两点,且△ ABC为直角三角形.若抛物线的对称轴交X轴于H,点P 为BH上任一点,连接 PC,作∠PCQ=45交X轴的正半轴于Q,若P(a,0) ,Q(b,0) ,试求a .b之间满足
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/19 04:12:43
![已知抛物线Y=ax2+bx+c的顶点C(1,—2),与X轴交于A,B两点,且△ ABC为直角三角形.若抛物线的对称轴交X轴于H,点P 为BH上任一点,连接 PC,作∠PCQ=45交X轴的正半轴于Q,若P(a,0) ,Q(b,0) ,试求a .b之间满足](/uploads/image/z/3716948-20-8.jpg?t=%E5%B7%B2%E7%9F%A5%E6%8A%9B%E7%89%A9%E7%BA%BFY%3Dax2%2Bbx%2Bc%E7%9A%84%E9%A1%B6%E7%82%B9C%EF%BC%881%2C%E2%80%942%EF%BC%89%2C%E4%B8%8EX%E8%BD%B4%E4%BA%A4%E4%BA%8EA%2CB%E4%B8%A4%E7%82%B9%2C%E4%B8%94%E2%96%B3+ABC%E4%B8%BA%E7%9B%B4%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A2.%E8%8B%A5%E6%8A%9B%E7%89%A9%E7%BA%BF%E7%9A%84%E5%AF%B9%E7%A7%B0%E8%BD%B4%E4%BA%A4X%E8%BD%B4%E4%BA%8EH%2C%E7%82%B9P+%E4%B8%BABH%E4%B8%8A%E4%BB%BB%E4%B8%80%E7%82%B9%2C%E8%BF%9E%E6%8E%A5+PC%2C%E4%BD%9C%E2%88%A0PCQ%3D45%E4%BA%A4X%E8%BD%B4%E7%9A%84%E6%AD%A3%E5%8D%8A%E8%BD%B4%E4%BA%8EQ%2C%E8%8B%A5P%EF%BC%88a%2C0%29+%2CQ%28b%2C0%29+%2C%E8%AF%95%E6%B1%82a+.b%E4%B9%8B%E9%97%B4%E6%BB%A1%E8%B6%B3)
xSMo@++U@,HV*F}hڣ{GBc4)PC
)ېv_؋H꭪Tٙf>i{e[Zw-Ȏ]\D^:F)ab_zUDkȁpsqDI&G^%xU̫ ,OހpzVLly;c.RdL'sBUak{UXCkeb R[
oVCzzCv[PL'hKo