(2x-1)²-3(2x-1)+4=00.2分之(X²+2x+6)=0.3分之(1-x+x²)
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(2x-1)²-3(2x-1)+4=00.2分之(X²+2x+6)=0.3分之(1-x+x²)
(2x-1)²-3(2x-1)+4=0
0.2分之(X²+2x+6)=0.3分之(1-x+x²)
(2x-1)²-3(2x-1)+4=00.2分之(X²+2x+6)=0.3分之(1-x+x²)
1.(2x-1)²-3(2x-1)+4=0
令t=2x-1,则:
t²-3t+4=0
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