三角形ABC中角ABC=角ACB,D为BC边上一点,E为直线AC上一点 且角ADE=角AED求证:∠BAD=2∠CDE
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![三角形ABC中角ABC=角ACB,D为BC边上一点,E为直线AC上一点 且角ADE=角AED求证:∠BAD=2∠CDE](/uploads/image/z/3720967-7-7.jpg?t=%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%E8%A7%92ABC%3D%E8%A7%92ACB%2CD%E4%B8%BABC%E8%BE%B9%E4%B8%8A%E4%B8%80%E7%82%B9%2CE%E4%B8%BA%E7%9B%B4%E7%BA%BFAC%E4%B8%8A%E4%B8%80%E7%82%B9+%E4%B8%94%E8%A7%92ADE%3D%E8%A7%92AED%E6%B1%82%E8%AF%81%EF%BC%9A%E2%88%A0BAD%3D2%E2%88%A0CDE)
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