已知a b c 是△abc的三边,且a b c满足等式b²=(c+a)(c-a).且5a-4a=0.(1)判断△abc的形状(2)求tanA tanB的值(3)求sinA+sinB的值5a-4c=0
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![已知a b c 是△abc的三边,且a b c满足等式b²=(c+a)(c-a).且5a-4a=0.(1)判断△abc的形状(2)求tanA tanB的值(3)求sinA+sinB的值5a-4c=0](/uploads/image/z/3721580-44-0.jpg?t=%E5%B7%B2%E7%9F%A5a+b+c+%E6%98%AF%E2%96%B3abc%E7%9A%84%E4%B8%89%E8%BE%B9%2C%E4%B8%94a+b+c%E6%BB%A1%E8%B6%B3%E7%AD%89%E5%BC%8Fb%26sup2%3B%3D%28c%2Ba%29%28c-a%29.%E4%B8%945a-4a%3D0.%281%29%E5%88%A4%E6%96%AD%E2%96%B3abc%E7%9A%84%E5%BD%A2%E7%8A%B6%EF%BC%882%EF%BC%89%E6%B1%82tanA+tanB%E7%9A%84%E5%80%BC%EF%BC%883%EF%BC%89%E6%B1%82sinA%2BsinB%E7%9A%84%E5%80%BC5a-4c%3D0)
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