帮我分析一下这个二分取幂的原理,这个算法可以求出2^x,2的x次幂 c++的long long func(int x){\x05if(x==0) return 1;\x05long long res;\x05res=func(x/2);\x05res*=res;\x05if(x%2==1)\x05res*=2;\x05return (res%1234567);}
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![帮我分析一下这个二分取幂的原理,这个算法可以求出2^x,2的x次幂 c++的long long func(int x){\x05if(x==0) return 1;\x05long long res;\x05res=func(x/2);\x05res*=res;\x05if(x%2==1)\x05res*=2;\x05return (res%1234567);}](/uploads/image/z/3722735-47-5.jpg?t=%E5%B8%AE%E6%88%91%E5%88%86%E6%9E%90%E4%B8%80%E4%B8%8B%E8%BF%99%E4%B8%AA%E4%BA%8C%E5%88%86%E5%8F%96%E5%B9%82%E7%9A%84%E5%8E%9F%E7%90%86%2C%E8%BF%99%E4%B8%AA%E7%AE%97%E6%B3%95%E5%8F%AF%E4%BB%A5%E6%B1%82%E5%87%BA2%5Ex%2C2%E7%9A%84x%E6%AC%A1%E5%B9%82+c%2B%2B%E7%9A%84long+long+func%28int+x%29%7B%5Cx05if%28x%3D%3D0%29+return+1%3B%5Cx05long+long+res%3B%5Cx05res%3Dfunc%28x%2F2%29%3B%5Cx05res%2A%3Dres%3B%5Cx05if%28x%252%3D%3D1%29%5Cx05res%2A%3D2%3B%5Cx05return+%28res%251234567%29%3B%7D)
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帮我分析一下这个二分取幂的原理,这个算法可以求出2^x,2的x次幂 c++的long long func(int x){\x05if(x==0) return 1;\x05long long res;\x05res=func(x/2);\x05res*=res;\x05if(x%2==1)\x05res*=2;\x05return (res%1234567);}
帮我分析一下这个二分取幂的原理,这个算法可以求出2^x,2的x次幂 c++的
long long func(int x)
{
\x05if(x==0) return 1;
\x05long long res;
\x05res=func(x/2);
\x05res*=res;
\x05if(x%2==1)
\x05res*=2;
\x05return (res%1234567);
}
帮我分析一下这个二分取幂的原理,这个算法可以求出2^x,2的x次幂 c++的long long func(int x){\x05if(x==0) return 1;\x05long long res;\x05res=func(x/2);\x05res*=res;\x05if(x%2==1)\x05res*=2;\x05return (res%1234567);}
当x为偶数2k时,2^x=(2^k))^2,
当x为奇数2k+1时,2^x=2*(2^k)^2